Tightness and Euler Characteristic
The Gauss-Bonnet theorem tells us
$$\chi(M) = {1\over 2\pi} \int_M K\,dx,$$
so if $K$ doesn't change sign, then $\chi(M)$ has the same sign as $K$.
Theorem: a surface in a CES is tight if, and only if, its curvature
always has the same sign as its Euler characteristic.
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