In problem 5c and 5e the integral of 1/u du will appear if you do
the expected u substitution. This is an integral we haven't figures
out how to handle yet, so these problems are not possible for you at
this point. Try instead:
/
| 1 + x
5c | ------- dx
| 3
/ x
/
| sin x
5e | --------- dx
| 2
/ (1+cos x)
Problem 6a suffers from the same problem as 5c and 5e above.
Ignore it. Sorry.
In problem 6d the netgative sign should be a plus sign. That is,
the square root should be of 3sinx + 1.