5. (g) First note x1 = x'1 = a.

Next, y1 = b and y'1 = -b, so y1 = -y'1.

Then, note x2 = x'2 = a2 - b2 + a and y2 = 2*a*b + b, y'2 = 2*a*(-b) - b = -(2*a*b + b) = -y2.

Finally, assuming xn = x'n and yn = -y'n, then xn+1 = xn2 - yn2 + a and x'n+1 = x'n2 - y'n2 + a = xn2 - yn2 + a = xn+1. Also, yn+1 = 2*xn*yn + b and y'n+1 = 2*x'n*y'n - b = 2*xn*(-yn) - b = -(2*xn*yn + b) = yn+1.

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