14. (a) From equation

(1b) y_n+1 = 2*x_n*y_n + b

we see that if b = 0 and y_n = 0, then y_n+1 = 0.

(b) This follows from substituting y_n = 0 and b = 0 into equations

(1a) x_n+1 = x_n² - y_n² + a

and (1b).

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