41.For x₀ = 1/4ⁿ, applying equation (2)

x_n+1 = s*x_n for x_n < 1/2

we see x₁ = 1/4^n-1, x₂ = 1/4^n-2, ... , x_n-1 = 1/4, x_n = 1, and x_n+1 = 1.

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